Error could not open requirements file errno 2 no such file or directory requirements txt

‘RUN pip install -r requirements.txt’ not working

I am new to Docker and trying to deploy a django project with the same. But after building the docker-compose I am getting this error:

ERROR: Could not open requirements file: [Errno 2] No such file or directory: ‘requirements.txt’ ERROR: Service ‘web’ failed to build: The command ‘/bin/sh -c pip install -r requirements.txt’ returned a non-zero code: 1

I might be messing up in setting the correct path so here is my project structure

Here is my dockerfile

and this is my docker-compose.yml

2 Answers 2

Several issues I’m seeing:

• The ADD command you use creates a file called ToDoApp/ToDoApp , it doesn’t even create a sub directory.
• ADD is unneeded (you’re not extracting a tar or downloading from a URL) so that can switch to a COPY.
• You need to copy your code.
• The RUN commands can be reordered for better cache efficiency.
• Use relative paths and the WORKDIR correctly.
• Args need to be separated when you use the json syntax

The resulting Dockerfile looks like:

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Packages installed by `pip install -r requirements.txt` are not found

I’m trying to run an inherited Django project. I’ve set up a virtualenv and tried to pass in the requirements file via pip install -r requirements.txt . Everything seems to work. It tells me it’s working in the correct virtualenv, and packages appear to install, e.g.:

But when I try to syncdb or runserver,

What’s weird is that I install mediasync (or any other necessary packages) manually ( pip install django-mediasync ), the package can now be found.

What am I doing wrong? I don’t want to have to install all of these packages manually.

2 Answers 2

I think when doing: pip install -r requirements.txt there was some error but you didn’t notice. Basically the whole operation will stop at the time there is error.

So for example your requirements.txt have 4 packages like this:

If there is an error when installing B , 3 packages B , C and D will not be installed. It seems to me that there was an error with installation of one package in your requirements.txt and it didn’t install django-mediasync at all.

If my hypothesis is right, please do pip install -r requirements.txt and check the last part of the traceback. If something fails, you will know exactly why.

Are you doing sudo pip install django-mediasync or sudo pip install -r requirements.txt ? If so, it’ll install it outside of the virtualenv. See How to install which programs requires «sudo» in virtualenv?.

Basically because your user should own the virtualenv directory, you don’t need superuser privileges to install anything via pip. Do which pip and sudo which pip and you will see they are different.

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pip install -r requirements.txt [Errno 2] No such file or directory: ‘requirements.txt’

I am setting up the base for a django project, I have cloned a repo and I have just created a virtual environment for the project in the same directory. But when I try to run the command pip install -r requirements.txt in the project directory I get this error:

[Errno 2] No such file or directory: ‘requirements.txt’

I believe I’m just running it in the wrong directory, but I don’t really know where I should run it. Do you have any idea where the file could be located?

16 Answers 16

If you are using a virtual environment just use the following line.

pip freeze > requirements.txt

It commands to create the requirements file first.

Or in dockerfile, RUN pip freeze > requirements.txt .

If you are facing this issue while using a docker or flowing getting started guide from docker site then you need to update your Docker file.

just add following line to create the requirements.txt file before the line «RUN pip install —no-cache-dir -r requirements.txt» in your Dockerfile

A better way of doing this is write this on the root directory of your terminal:

It will search in your root directory and all subfolders for a file called requirements.txt . After the command response, you can get the directory and run the pip install -r requirements.txt on it.

Try using this in your terminal then go to the directory and use the pip install command.

I tried this and solved:

Well, I got the same kind of error cmd code image and this is how I resolved it.

If you see an error it is because I named my text document as ‘requirements.txt’ and not ‘requirements’, the .txt addition will be done by Windows itself we don’t need to bother about that.

Finally, implement your code: pip install -r requirements.txt see the code is not showing an error now

I faced the same issue and this is because I wrote the RUN instruction before COPY instruction, so make sure to write it in the correct order.

if you are on Mac os

I solved this problem by indicating the full path to file (for example):

Check if you have requirements.txt file in the directory.
and then run the following command.
pip install -r requirements.txt

Make sure the requirements.txt file is in the same folder where you are installing it using pip install -r requirements.txt

I had this problem, 3 years too late however move the req file into downloads and then try it again

it gives «pip install -r requirements.txt [Errno 2] No such file or directory: ‘requirements.txt’, » times and times, with the codes

1. python –m venv env
2. envScriptsactivate
3. pip install – r requirements.txt
   . after the codes are below, I write. It runs.
4. python –m venv xenv (with different env’s name)
5. envScriptsactivate
6. pip install – r requirements.txt
   . it runs. the file names in the requirements.txt are underlined with red, but it runs and it accepts, opens the files, and app runs.

Please check the command which you are running, I faced the same issue and after few minutes of search, I found I am placing a space in between mysql -connector .

Источник

Problems with pip or pip3 install requirements.txt what I should to do to fix this error?

I run into the error below when running either command lines;

ERROR: Command errored out with exit status 1: command: /usr/bin/python3 -c ‘import sys, setuptools, tokenize; sys.argv[0] = ‘»‘»‘/tmp/pip-install-evkbiocv/poster/setup.py’»‘»‘; file=’»‘»‘/tmp/pip-install-evkbiocv/poster/setup.py’»‘»‘;f=getattr(tokenize, ‘»‘»‘open’»‘»‘, open)(file);code=f.read().replace(‘»‘»‘rn’»‘»‘, ‘»‘»‘n’»‘»‘);f.close();exec(compile(code, file, ‘»‘»‘exec’»‘»‘))’ egg_info —egg-base /tmp/pip-install-evkbiocv/poster/pip-egg-info
cwd: /tmp/pip-install-evkbiocv/poster/
Complete output (10 lines):
Traceback (most recent call last):
File «», line 1, in
File «/tmp/pip-install-evkbiocv/poster/setup.py», line 2, in
import poster
File «/tmp/pip-install-evkbiocv/poster/poster/init.py», line 29, in
import poster.streaminghttp
File «/tmp/pip-install-evkbiocv/poster/poster/streaminghttp.py», line 61
print «send:», repr(value)
^
SyntaxError: invalid syntax
—————————————-
ERROR: Command errored out with exit status 1: python setup.py egg_info Check the logs for full command output.`

What am I doing wrong and how can I fix it?

1 Answer 1

poster — the latest version was released in 2011. Obviously the package is for Python 2 and abandoned.

Источник

Problems with pip or pip3 install requirements.txt what I should to do to fix this error?

I run into the error below when running either command lines;

ERROR: Command errored out with exit status 1: command: /usr/bin/python3 -c ‘import sys, setuptools, tokenize; sys.argv[0] = ‘»‘»‘/tmp/pip-install-evkbiocv/poster/setup.py’»‘»‘; file=’»‘»‘/tmp/pip-install-evkbiocv/poster/setup.py’»‘»‘;f=getattr(tokenize, ‘»‘»‘open’»‘»‘, open)(file);code=f.read().replace(‘»‘»‘rn’»‘»‘, ‘»‘»‘n’»‘»‘);f.close();exec(compile(code, file, ‘»‘»‘exec’»‘»‘))’ egg_info —egg-base /tmp/pip-install-evkbiocv/poster/pip-egg-info
cwd: /tmp/pip-install-evkbiocv/poster/
Complete output (10 lines):
Traceback (most recent call last):
File «», line 1, in
File «/tmp/pip-install-evkbiocv/poster/setup.py», line 2, in
import poster
File «/tmp/pip-install-evkbiocv/poster/poster/init.py», line 29, in
import poster.streaminghttp
File «/tmp/pip-install-evkbiocv/poster/poster/streaminghttp.py», line 61
print «send:», repr(value)
^
SyntaxError: invalid syntax
—————————————-
ERROR: Command errored out with exit status 1: python setup.py egg_info Check the logs for full command output.`

What am I doing wrong and how can I fix it?

1 Answer 1

poster — the latest version was released in 2011. Obviously the package is for Python 2 and abandoned.

Источник

Like any programming language, an error in python occurs when a given code fails to follow the syntax rules. When a code does not follow the syntax, python cannot recognize that segment of code, so it throws an error. Errors can be of different types, such as runtime error, syntax error, logical error, etc. IOError errno 2 no such file or directory is one such type of error. Let us first understand each individual term of the error.

Note : Starting from Python 3.3, IOError is an aliases of OSError

What is IOError?

An IOError is thrown when an input-output operation fails in the program. The common input-output operations are opening a file or a directory, executing a print statement, etc. IOError is inherited from the EnvironmentError. The syntax of IOError is:

IOError : [Error number] ‘Reason why the error occurred’: ‘name of the file because of which the error occurred’

Examples of IOError are :

• Unable to execute the open() statement because either the filename is incorrect or the file is not present in the specified location.
• Unable to execute the print() statements because either the disk is full or the file cannot be found
• The permission to access the particular file is not given.

What is errno2 no such file or directory?

The ‘errorno 2 no such file or directory‘ is thrown when you are trying to access a file that is not present in the particular file path or its name has been changed.

This error is raised either by ‘FileNotFoundError’ or by ‘IOError’. The ‘FileNotFoundError’ raises ‘errorno 2 no such file or directory‘ when using the os library to read a given file or a directory, and that operation fails.

The ‘IOError’ raises ‘errorno 2 no such file or directory‘ when trying to access a file that does not exist in the given location using the open() function.

Handling ‘IOError [errorno 2] no such file or directory’

‘IOError errorno 2 no such file or directory‘ occurs mainly while we are handling the open() function for opening a file. Therefore, we will look at several solutions to solve the above error.

We will check if a file exists, raise exceptions, solve the error occurring while installing ‘requirements.txt,’ etc.

Checking if the file exists beforehand

If a file or a directory does not exist, it will show ‘IOError [errorno 2] no such file or directory’ while opening it. Let us take an example of opening a file named ‘filename.txt’.

The given file does not exist and we shall see what happens if we try to execute it.

Since the above text file does not exist, it will throw the IOError.

Traceback (most recent call last):
  File "main.py", line 1, in <module>
    f = open('filename.txt')
IOError: [Errno 2] No such file or directory: 'filename.txt'

To avoid the above error from being thrown, we will use several methods which will first check if the file exists or not. It will execute the open() function only if the file exists.

We have two modules containing functions for checking if a file exists.

1. OS Module
2. Pathlib Module

Using the OS Module

In the os module, there are three functions which can be used:

• os.path.isfile()
• os.path.isdir()
• os.path.exists()

To solve the IOError, we can use either of the above function in a condition statement. We will pass the pathname of the file as an argument to the above functions.

If the file or the directory exists, the function shall return True else False. Bypassing either of the above functions as the conditional statement ensures that python will open a file only if it exists, thus preventing an error from occurring.

We will use os.path.isfile() when we want to check if a file exists or not, os.path.isdir() to check if a directory exists or not and os.path.exists() to check if a path exists or not.

Since we want to check for a file, we can use either the os.path.isfile() function or os.path.exists() function. We shall apply the function to the above example.

import os

path_name = "filename.txt"

if os.path.isfile(path_name):
  print("File exists")
  f = open(path_name)
  #Execute other file operations here
  f.close()
  
else:
  print("File does not exist! IOError has occured")

First, we have imported the os module. Then we have a variable named ‘path_name‘ which stores the path for the file.

We passed the path_name as an argument to the os.path.isfile() function. If the os.path.isfile() function returns a true value. Then it will print “File exists” and execute the other file operations.

If the file does not exist, then it will print the second statement in the else condition. Unlike the previous case, here, it will not throw an error and print the message.

File does not exist! IOError has occured

Similarly, we can also use os.path.exists() function.

Using the pathlib module

The pathlib module contains three functions – pathlib.Path.exists(), pathlib.Path.is_dir() and pathlib.Path.is_file().

We will use pathlib.Path.is_file() in this example. Just like the os module, we will use the function in an if conditional statement.

It will execute the open() function only if the file exists. Thus it will not throw an error.

from pathlib import Path
path_name = "filename.txt"
p = Path(path_name)
if p.is_file():
  print("File exists")
  f = open(path_name)
  #Execute other file operations here
  f.close()
  
else:
  print("File does not exist! IOError has occured")

Since the file does not exist, the output is :

File does not exist! IOError has occured

Using try – except block

We can also use exception handling for avoiding ‘IOError Errno 2 No Such File Or Directory’. In the try block, we will try to execute the open() function.

If the file is present, it will execute the open() function and all the other file operations mentioned in the try block. But, if the file cannot be found, it will throw an IOError exception and execute the except block.

try:
    f = open("filename.txt")
    #Execute other operations
    f.close()
except IOError as io:
    print(io)

Here, it will execute the except block because ‘filename.txt’ does not exist. Instead of throwing an error, it will print the IOError.

[Errno 2] No such file or directory: 'filename.txt'

We can also print a user defined message in the except block.

try:
    f = open("filename.txt")
    #Execute other operations
    f.close()
except IOError:
    print("File does not exist. IOError has occured")

The output will be:

File does not exist. IOError has occured

IOError errno 2 no such file or directory in requirements.txt

Requirements.txt is a file containing all the dependencies in a project and their version details.

Basically, it contains the details of all the packages in python needed to run the project. We use the pip install command to install the requirements.txt file. But it shows the ‘IOError errno 2 no such file or directory’ error.

!pip install -r requirements.txt

The thrown error is:

ERROR: Could not open requirements file: [Errno 2] No such file or directory: 'requirements.txt'

To solve the above error, we use the pip freeze command. When we use pip freeze, the output will contain the package along with its version.

The output will be in a configuration that we will use with the pip install command.

pip freeze > requirements.txt

Now, we will try to execute the pip install command again. It will no longer throw errors and all the packages will be installed successfully.

Opening file in ‘w+’ mode

While trying to open a text file, the default mode will be read mode. In that case, it will throw the ‘IOError Errno 2 No Such File Or Directory’ error.

f = open("filename.txt")
f.close()
print("Successful")

The output is:

Traceback (most recent call last):
  File "main.py", line 1, in <module>
    f = open("filename.txt")
IOError: [Errno 2] No such file or directory: 'filename.txt'

To solve the error, we can open the file in ‘w+’ mode. This will open the file in both – reading and writing mode. If the file does not exist, it will create a new file, and if the file exists, it will overwrite the contents of the file. This way, it will not throw an error.

f = open("filename.txt", 'w+')
f.close()
print("Successful")

The output is:

Successful

Apart from all the above methods, there are some ways to ensure that the IOError does not occur. You have to ensure that you are giving the absolute path as the path name and not simply the name of the file.

Also, see to that there are no escape sequences in the path name of this file.

For example : In path_name = "C:name.txt ", it will consider the 'n' from 'name.txt' as an escape sequence. 

So, it will not be able to find the file 'name.txt'.

Also, Read

• How to Solve “unhashable type: list” Error in Python
• How to solve Type error: a byte-like object is required not ‘str’
• Invalid literal for int() with base 10 | Error and Resolution
• How to Solve TypeError: ‘int’ object is not Subscriptable

This sums up everything about IOError Errno 2 No Such File Or Directory. If you have any questions, do let us know in the comments below.

Until then, Keep Learning!